3[x-(2-x)-2x]=3(4-x)

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Solution for 3[x-(2-x)-2x]=3(4-x) equation:


Simplifying
3[x + -1(2 + -1x) + -2x] = 3(4 + -1x)
3[x + (2 * -1 + -1x * -1) + -2x] = 3(4 + -1x)
3[x + (-2 + 1x) + -2x] = 3(4 + -1x)

Reorder the terms:
3[-2 + x + 1x + -2x] = 3(4 + -1x)

Combine like terms: x + 1x = 2x
3[-2 + 2x + -2x] = 3(4 + -1x)

Combine like terms: 2x + -2x = 0
3[-2 + 0] = 3(4 + -1x)
3[-2] = 3(4 + -1x)

Multiply 3 * -2
-6 = 3(4 + -1x)
-6 = (4 * 3 + -1x * 3)
-6 = (12 + -3x)

Solving
-6 = 12 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
-6 + 3x = 12 + -3x + 3x

Combine like terms: -3x + 3x = 0
-6 + 3x = 12 + 0
-6 + 3x = 12

Add '6' to each side of the equation.
-6 + 6 + 3x = 12 + 6

Combine like terms: -6 + 6 = 0
0 + 3x = 12 + 6
3x = 12 + 6

Combine like terms: 12 + 6 = 18
3x = 18

Divide each side by '3'.
x = 6

Simplifying
x = 6

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